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x^2+300x-1800000=0
a = 1; b = 300; c = -1800000;
Δ = b2-4ac
Δ = 3002-4·1·(-1800000)
Δ = 7290000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7290000}=2700$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-2700}{2*1}=\frac{-3000}{2} =-1500 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+2700}{2*1}=\frac{2400}{2} =1200 $
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